olymmath

JBMO-SL 2018 A4

  • Answer

Let k>1,n>2018k>1, n>2018 be positive integers, and let nn be odd. The nonzero rational numbers x1x_{1}, x2,…,xnx_{2}, \ldots, x_{n} are not all equal and satisfy

x1+kx2=x2+kx3=x3+kx4=⋯=xn−1+kxn=xn+kx1x_{1}+\frac{k}{x_{2}}=x_{2}+\frac{k}{x_{3}}=x_{3}+\frac{k}{x_{4}}=\cdots=x_{n-1}+\frac{k}{x_{n}}=x_{n}+\frac{k}{x_{1}}

Find:

a) the product x1x2…xnx_{1} x_{2} \ldots x_{n} as a function of kk and nn

b) the least value of kk, such that there exist n,x1,x2,…,xnn, x_{1}, x_{2}, \ldots, x_{n} satisfying the given conditions.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

k=4

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator jbmo-sl/2018/a4 · Tag 5FTK554WJ7 · Edit this page on GitHub · Keys: j next, k previous