olymmath

JBMO-SL 2016 G2

    Let ABCA B C be a triangle with m(BAC^)=60∘m(\widehat{B A C})=60^{\circ}. Let DD and EE be the feet of the perpendiculars from AA to the external angle bisectors of ABC^\widehat{A B C} and ACB^\widehat{A C B}, respectively. Let OO be the circumcenter of the triangle ABCA B C. Prove that the circumcircles of the triangles △ADE\triangle A D E and △BOC\triangle B O C are tangent to each other.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator jbmo-sl/2016/g2 · Tag V5DVTB2TM8 · Edit this page on GitHub · Keys: j next, k previous