olymmath

JBMO-SL 2008 G6

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Let ABCA B C be a triangle with A<90∘A<90^{\circ}. Outside of a triangle we consider isosceles triangles ABEA B E and ACZA C Z with bases ABA B and ACA C, respectively. If the midpoint DD of the side BCB C is such that DE⊥DZD E \perp D Z and EZ=2⋅EDE Z=2 \cdot E D, prove that AEB^=2⋅AZC^\widehat{A E B}=2 \cdot \widehat{A Z C}.

Dataset text NuminaMath olympiads. Quoted with source.

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\widehat{A E B}=2 \cdot \widehat{A Z C}

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