olymmath

ISL 2023 G4

    Let ABCA B C be an acute-angled triangle with AB<ACA B<A C. Denote its circumcircle by Ω\Omega and denote the midpoint of arc CABC A B by SS. Let the perpendicular from AA to BCB C meet BSB S and Ω\Omega at DD and E≠AE \neq A respectively. Let the line through DD parallel to BCB C meet line BEB E at LL and denote the circumcircle of triangle BDLB D L by ω\omega. Let ω\omega meet Ω\Omega again at P≠BP \neq B. Prove that the line tangent to ω\omega at PP, and line BSB S intersect on the internal bisector of ∠BAC\angle B A C. (Portugal)

    Official text Transcription from NuminaMath olympiads, checked word for word against the official paper. Quoted with source.

    Official text: IMO 2023 Shortlist booklet, page 9.

    Solutions

    Official solution Solution 1 by the IMO Problem Selection Committee

    The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

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