olymmath

ISL 2023 C4

  • Answer

Let n⩾2n \geqslant 2 be a positive integer. Paul has a 1×n21 \times n^{2} rectangular strip consisting of n2n^{2} unit squares, where the ith i^{\text {th }} square is labelled with ii for all 1⩽i⩽n21 \leqslant i \leqslant n^{2}. He wishes to cut the strip into several pieces, where each piece consists of a number of consecutive unit squares, and then translate (without rotating or flipping) the pieces to obtain an n×nn \times n square satisfying the following property: if the unit square in the ith i^{\text {th }} row and jth j^{\text {th }} column is labelled with aija_{i j}, then aij−(i+j−1)a_{i j}-(i+j-1) is divisible by nn. Determine the smallest number of pieces Paul needs to make in order to accomplish this.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

2n-1

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator isl/2023/c4 · Tag PP1HY7BE7M · Edit this page on GitHub · Keys: j next, k previous