olymmath

ISL 2014 G6

  • Answer

Let ABCA B C be a fixed acute-angled triangle. Consider some points EE and FF lying on the sides ACA C and ABA B, respectively, and let MM be the midpoint of EFE F. Let the perpendicular bisector of EFE F intersect the line BCB C at KK, and let the perpendicular bisector of MKM K intersect the lines ACA C and ABA B at SS and TT, respectively. We call the pair (E,F)(E, F) interesting, if the quadrilateral KSATK S A T is cyclic. Suppose that the pairs (E1,F1)\left(E_{1}, F_{1}\right) and (E2,F2)\left(E_{2}, F_{2}\right) are interesting. Prove that E1E2AB=F1F2AC\frac{E_{1} E_{2}}{A B}=\frac{F_{1} F_{2}}{A C} (Iran)

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{E_{1} E_{2}}{A B}=\frac{F_{1} F_{2}}{A C}

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