olymmath

ISL 2013 C7

    Let n⩾2n \geqslant 2 be an integer. Consider all circular arrangements of the numbers 0,1,…,n0,1, \ldots, n; the n+1n+1 rotations of an arrangement are considered to be equal. A circular arrangement is called beautiful if, for any four distinct numbers 0⩽a,b,c,d⩽n0 \leqslant a, b, c, d \leqslant n with a+c=b+da+c=b+d, the chord joining numbers aa and cc does not intersect the chord joining numbers bb and dd. Let MM be the number of beautiful arrangements of 0,1,…,n0,1, \ldots, n. Let NN be the number of pairs (x,y)(x, y) of positive integers such that x+y⩽nx+y \leqslant n and gcd⁡(x,y)=1\operatorname{gcd}(x, y)=1. Prove that M=N+1M=N+1 (Russia)

    Dataset text NuminaMath olympiads. Quoted with source.

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