olymmath

ISL 1998 N4

A sequence of integers a1,a2,a3,…a_{1},a_{2},a_{3},\ldots is defined as follows: a1=1a_{1} = 1 and for n≥1n\geq 1 , an+1a_{n + 1} is the smallest integer greater than ana_{n} such that ai+aj≠3aka_{i} + a_{j}\neq 3a_{k} for any i,ji,j and kk in {1,2,3,…,n+1}\{1,2,3,\ldots ,n + 1\} , not necessarily distinct. Determine a1998a_{1998} .

Attachments:

IMO98.gif

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator isl/1998/n4 · Tag ZE5B2KJP8W · Edit this page on GitHub · Keys: j next, k previous