olymmath

ISL 1992

IMO Shortlist 1992.

Other problems

Problem 1

Prove that for any positive integer mm there exist an infinite number of pairs of integers (x,y)(x, y) such that

(i) xx and yy are relatively prime; (ii) yy divides x2+mx^2 + m ; (iii) xx divides y2+m.y^2 + m. (iv) x+y≤m+1−x + y \leq m + 1- (optional condition)

Problem 2

Let R+\mathbb{R}^+ be the set of all non-negative real numbers. Given two positive real numbers aa and b,b, suppose that a mapping f:R+↦R+f: \mathbb{R}^+ \mapsto \mathbb{R}^+ satisfies the functional equation:

f(f(x))+af(x)=b(a+b)x.f(f(x)) + af(x) = b(a + b)x.

Prove that there exists a unique solution of this equation.

Problem 3

The diagonals of a quadrilateral ABCDABCD are perpendicular: AC⊥BD.AC \perp BD. Four squares, ABEF,BCGH,CDIJ,DAKL,ABEF,BCGH,CDIJ,DAKL, are erected externally on its sides. The intersection points of the pairs of straight lines CL,DF,AH,BJCL, DF, AH, BJ are denoted by P1,Q1,R1,S1,P_1,Q_1,R_1, S_1, respectively (left figure), and the intersection points of the pairs of straight lines AI,BK,CEDGAI, BK, CE DG are denoted by P2,Q2,R2,S2,P_2,Q_2,R_2, S_2, respectively (right figure). Prove that P1Q1R1S1≅P2Q2R2S2P_1Q_1R_1S_1 \cong P_2Q_2R_2S_2 where P1,Q1,R1,S1P_1,Q_1,R_1, S_1 and P2,Q2,R2,S2P_2,Q_2,R_2, S_2 are the two quadrilaterals.

Alternative formulation: Outside a convex quadrilateral ABCDABCD with perpendicular diagonals, four squares AEFB,BGHC,CIJD,DKLA,AEFB, BGHC, CIJD, DKLA, are constructed (vertices are given in counterclockwise order). Prove that the quadrilaterals Q1Q_1 and Q2Q_2 formed by the lines AG,BI,CK,DEAG, BI, CK, DE and AJ,BL,CF,DH,AJ, BL, CF, DH, respectively, are congruent.

Attachments:

IMO_Shortlist_1992_Problem_3.jpg

Problem 5

A convex quadrilateral has equal diagonals. An equilateral triangle is constructed on the outside of each side of the quadrilateral. The centers of the triangles on opposite sides are joined. Show that the two joining lines are perpendicular.

Alternative formulation. Given a convex quadrilateral ABCDABCD with congruent diagonals AC=BD.AC = BD. Four regular triangles are errected externally on its sides. Prove that the segments joining the centroids of the triangles on the opposite sides are perpendicular to each other.

Original formulation: Let ABCDABCD be a convex quadrilateral such that AC=BD.AC = BD. Equilateral triangles are constructed on the sides of the quadrilateral. Let O1,O2,O3,O4O_1,O_2,O_3,O_4 be the centers of the triangles constructed on AB,BC,CD,DAAB,BC,CD,DA respectively. Show that O1O3O_1O_3 is perpendicular to O2O4.O_2O_4.