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IR-TST 2017 Problem 18

  • Test 3

In triangle ABCABC let OO and HH be the circumcenter and the orthocenter. The point PP is the reflection of AA with respect to OHOH . Assume that PP is not on the same side of BCBC as AA . Points E,FE,F lie on AB,ACAB,AC respectively such that BE=PC ,CF=PBBE=PC \ , CF=PB . Let KK be the intersection point of AP,OHAP,OH . Prove that ∠EKF=90∘\angle EKF = 90 ^{\circ} Proposed by Iman Maghsoudi

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