olymmath

IR-TST 2015 Problem 7

  • Test 2

a,b,c,da,b,c,d are positive numbers such that ∑cyc1ab=1\sum_{cyc} \frac{1}{ab} =1 . Prove that : abcd+16≥8(a+c)(1a+1c)+8(b+d)(1b+1d)abcd+16 \geq 8 \sqrt{(a+c)(\frac{1}{a} + \frac{1}{c})}+8\sqrt{(b+d)(\frac{1}{b}+\frac{1}{d})}

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