IR-TST 2014 Problem 15 Test 3 let m,n∈Nm,n\in \mathbb{N}m,n∈N and p(x),q(x),h(x)p(x),q(x),h(x)p(x),q(x),h(x) are polynomials with real Coefficients such that p(x)p(x)p(x) is Descending. and for all x∈Rx\in \mathbb{R}x∈R p(q(nx+m)+h(x))=n(q(p(x))+h(x))+mp(q(nx+m)+h(x))=n(q(p(x))+h(x))+mp(q(nx+m)+h(x))=n(q(p(x))+h(x))+m . prove that dont exist function f:R→Rf:\mathbb{R}\rightarrow \mathbb{R}f:R→R such that for all x∈Rx\in \mathbb{R}x∈R f(q(p(x))+h(x))=f(x)2+1f(q(p(x))+h(x))=f(x)^{2}+1f(q(p(x))+h(x))=f(x)2+1 Dataset text AI-MO AoPS. Quoted with source. Solutions No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label. Add a solution Similar problems These problems have the most words in common with this statement. SILK-ROAD 2008 Problem 4IR-MO 2004 Problem 30BxMO 2010 Problem 2HMIC 2016 Problem 3BALTIC-WAY 2011 Problem 5 PreviousProblem 14 NextProblem 16 Locator ir-tst/2014/p15 · Tag BESSYE74YP · Edit this page on GitHub · Keys: j next, k previous