olymmath

IR-TST 2014 Problem 10

  • Test 2

nn is a natural number. We shall call a permutation a1,…,ana_1,\dots,a_n of 1,…,n1,\dots,n a quadratic(cubic) permutation if ∀1≤i≤n−1\forall 1\leq i \leq n-1 we have aiai+1+1a_ia_{i+1}+1 is a perfect square(cube). (a)(a) Prove that for infinitely many natural numbers nn there exists a quadratic permutation. (b)(b) Prove that for no natural number nn exists a cubic permutation.

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator ir-tst/2014/p10 · Tag RB1B2E65ER · Edit this page on GitHub · Keys: j next, k previous