olymmath

IR-MO 2009 Problem 8

    Sone of vertices of the infinite grid Z2\mathbb{Z}^{2} are missing. Let's take the remainder as a graph. Connect two edges of the graph if they are the same in one component and their other components have a difference equal to one. Call every connected component of this graph a branch. Suppose that for every natural nn the number of missing vertices in the (2n+1)×(2n+1)(2n+1)\times(2n+1) square centered by the origin is less than n2\frac{n}{2} . Prove that among the branches of the graph, exactly one has an infinite number of vertices.

    Time allowed for this problem was 90 minutes.

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    1388-khallaghiat-iranian_mathematical_olympiad.pdf - Adobe Reader.jpg

    Dataset text AI-MO AoPS. Quoted with source.

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