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IR-MO 2004 Problem 14

    We define f:N→Nf: \mathbb{N} \rightarrow \mathbb{N} , f(n)=∑k=1n(k,n)f(n) = \sum_{k = 1}^{n}(k,n) .

    a) Show that if gcd⁡(m,n)=1\gcd(m,n)=1 then we have f(mn)=f(m)⋅f(n)f(mn)=f(m)\cdot f(n) ;

    b) Show that ∑d∣nf(d)=nd(n)\sum_{d|n}f(d) = nd(n) .

    Dataset text AI-MO AoPS. Quoted with source.

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