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IR-MO-R2 2013 Problem 2

    Let nn be a natural number and suppose that w1,w2,…,wnw_1, w_2, \ldots , w_n are nn weights . We call the set of {w1,w2,…,wn}\{ w_1, w_2, \ldots , w_n\} to be a Perfect Setif we can achieve all of the 1,2,…,W1,2, \ldots, W weights with sums of w1,w2,…,wnw_1, w_2, \ldots , w_n , where W=∑i=1nwiW=\sum_{i=1}^n w_i . Prove that if we delete the maximum weight of a Perfect Set, the other weights make again a Perfect Set.

    Dataset text AI-MO AoPS. Quoted with source.

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