olymmath

RMO 2023

Indian Regional Mathematical Olympiad 2023.

Official paper

The official paper in 2 languages

English (paper1) · English (paper2)

Non-KV and Non-JNV

Problem 1

  • Non-KV and Non-JNV

Let N\mathbb{N} be the set of all positive integers and S={(a,b,c,d)∈N4:a2+b2+c2=d2}S=\left\{(a, b, c, d) \in \mathbb{N}^4: a^2+b^2+c^2=d^2\right\} . Find the largest positive integer mm such that mm divides abcd for all (a,b,c,d)∈S(a, b, c, d) \in S .

Answer, solutions and source

Problem 2

  • Non-KV and Non-JNV

Let ω\omega be a semicircle with ABA B as the bounding diameter and let CDC D be a variable chord of the semicircle of constant length such that C,DC, D lie in the interior of the arc ABA B . Let EE be a point on the diameter ABA B such that CEC E and DED E are equally inclined to the line ABA B . Prove that (a) the measure of ∠CED\angle C E D is a constant; (b) the circumcircle of triangle CEDC E D passes through a fixed point.

Answer, solutions and source

Problem 3

  • Non-KV and Non-JNV

For any natural number nn , expressed in base 10 , let s(n)s(n) denote the sum of all its digits. Find all natural numbers mm and nn such that m<nm<n and (s(n))2=m and (s(m))2=n.(s(n))^2=m \text { and }(s(m))^2=n .

Answer, solutions and source

Problem 4

  • Non-KV and Non-JNV

Let Ω1,Ω2\Omega_1, \Omega_2 be two intersecting circles with centres O1,O2O_1, O_2 respectively. Let ll be a line that intersects Ω1\Omega_1 at points A,CA, C and Ω2\Omega_2 at points B,DB, D such that A,B,C,DA, B, C, D are collinear in that order. Let the perpendicular bisector of segment ABA B intersect Ω1\Omega_1 at points P,QP, Q ; and the perpendicular bisector of segment CDC D intersect Ω2\Omega_2 at points R,SR, S such that P,RP, R are on the same side of ll . Prove that the midpoints of PR,QSP R, Q S and O1O2O_1 O_2 are collinear.

Answer, solutions and source

Problem 5

  • Non-KV and Non-JNV

Let n>k>1n>k>1 be positive integers. Determine all positive real numbers a1,a2,…,ana_1, a_2, \ldots, a_n which satisfy ∑i=1nkaik(k−1)aik+1=∑i=1nai=n.\sum_{i=1}^n \sqrt{\frac{k a_i^k}{(k-1) a_i^k+1}}=\sum_{i=1}^n a_i=n .

Answer, solutions and source

Problem 6

  • Non-KV and Non-JNV

Consider a set of 1616 points arranged in 4×44 \times 4 square grid formation. Prove that if any 77 of these points are coloured blue, then there exists an isosceles right-angled triangle whose vertices are all blue.

Answer, solutions and source

KV and JNV

K1

  • KV and JNV

Given a triangle ABCABC with ∠ACB=120∘.\angle ACB = 120^{\circ}. A point LL is marked in the side ABAB such that CLCL bisects ∠ACB.\angle ACB. Points NN and KK are chosen in the sides ACAC and BCBC such that CK+CN=CL.CK+CN=CL. Prove that the triangle KLNKLN is equilateral.

Answer, solutions and source

K2

  • KV and JNV

Given a prime number pp such that 2p2p is equal to the sum of the squares of some four consecutive positive integers. Prove that p−7p-7 is divisible by 36.

Answer, solutions and source

K3

  • KV and JNV

Let f(x)f(x) be a polynomial with real coefficients of degree 2. Suppose that for some pairwise distinct real numbers , a,b,ca,b,c we have:

f(a)=bc,f(b)=ac,f(c)=abf(a)=bc , f(b)=ac, f(c)=ab Dertermine f(a+b+c)f(a+b+c) in terms of a,b,ca,b,c .

Answer, solutions and source

K4

  • KV and JNV

The set XX of NN four-digit numbers formed from the digits 1,2,3,4,5,6,7,81,2,3,4,5,6,7,8 satisfies the following condition:

for any two different digits from 1,2,3,4,,6,7,81,2,3,4,,6,7,8 there exists a number in XX which contains both of them.

Determine the smallest possible value of NN .

Answer, solutions and source

K5

  • KV and JNV

The side lengths a,b,ca,b,c of a triangle ABCABC are positive integers. Let:

Tn=(a+b+c)2n−(a−b+c)2n−(a+b−c)2n+(a−b−c)2nT_{n}=(a+b+c)^{2n}-(a-b+c)^{2n}-(a+b-c)^{2n}+(a-b-c)^{2n}

for any positive integer nn . If T22T1=2023\frac{T_{2}}{2T_{1}}=2023 and a>b>ca>b>c , determine all possible perimeters of the triangle ABCABC .

Answer, solutions and source

K6

  • KV and JNV

The diagonals ACAC and BDBD of a cyclic quadrilateral ABCDABCD meet at PP . The point QQ is chosen on the segment BCBC so that PQPQ is perpendicular to ACAC . Prove that the line joining the centres of the circumcircles of triangles APDAPD and BQDBQD is parallel to ADAD .

Answer, solutions and source