olymmath

RMO 2019 Problem 2

    Let ABCABC be a triangle with circumcircle Ω\Omega and let GG be the centroid of triangle ABCABC . Extend AG,BGAG, BG and CGCG to meet the circle Ω\Omega again in A1,B1A_1, B_1 and C1C_1 . Suppose ∠BAC=∠A1B1C1,∠ABC=∠A1C1B1\angle BAC = \angle A_1 B_1 C_1, \angle ABC = \angle A_1 C_1 B_1 and ∠ACB=B1A1C1\angle ACB = B_1 A_1 C_1 . Prove that ABCABC and A1B1C1A_1 B_1 C_1 are equilateral triangles.

    Dataset text AI-MO AoPS. Quoted with source.

    Official text: Indian Regional Mathematical Olympiad 2019 official paper, page 1.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator in-rmo/2019/p2 · Tag 6HJ1SVTXQE · Edit this page on GitHub · Keys: j next, k previous