olymmath

RMO 2015 B2

  • CRMO Paper 2

Let P(x)=x2+ax+bP(x) = x^2 + ax + b be a quadratic polynomial with real coefficients. Suppose there are real numbers s≠ts \neq t such that P(s)=tP(s) = t and P(t)=sP(t) = s . Prove that b−stb-st is a root of x2+ax+b−stx^2 + ax + b - st .

Dataset text AI-MO AoPS. Quoted with source.

Official text: Indian Regional Mathematical Olympiad 2015 official paper, page 1.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator in-rmo/2015/b2 · Tag 6BRNYQN29G · Edit this page on GitHub · Keys: j next, k previous