olymmath

INMO 2021 Problem 5

    In a convex quadrilateral ABCDABCD , ∠ABD=30∘\angle ABD=30^\circ , ∠BCA=75∘\angle BCA=75^\circ , ∠ACD=25∘\angle ACD=25^\circ and CD=CBCD=CB . Extend CBCB to meet the circumcircle of triangle DACDAC at EE . Prove that CE=BDCE=BD .

    Proposed by BJ Venkatachala

    Dataset text AI-MO AoPS. Quoted with source.

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