olymmath

INMO 2006 Problem 5

    In a cyclic quadrilateral ABCD,AB=a,BC=b,CD=c,∠ABC=120∘A B C D, A B=a, B C=b, C D=c, \angle A B C=120^{\circ}, and ∠ABD=\angle A B D= 30∘30^{\circ}. Prove that

    (i) c≥a+bc \geq a+b;

    (ii) ∣c+a−c+b∣=c−a−b|\sqrt{c+a}-\sqrt{c+b}|=\sqrt{c-a-b}.

    Dataset text NuminaMath olympiads. Quoted with source.

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