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ILL 1992 Problem 1

    Points DD and EE are chosen on the sides ABAB and ACAC of the triangle ABCABC in such a way that if FF is the intersection point of BEBE and CDCD , then AE+EF=AD+DFAE + EF = AD + DF . Prove that AC+CF=AB+BF.AC + CF = AB + BF.

    Dataset text AI-MO AoPS. Quoted with source.

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