olymmath

ILL 1986 Problem 5

    Let ABCABC and DEFDEF be acute-angled triangles. Write d=EF,e=FD,f=DE.d = EF, e = FD, f = DE. Show that there exists a point PP in the interior of ABCABC for which the value of the expression X=d⋅AP+e⋅BP+f⋅CPX=d \cdot AP +e \cdot BP +f \cdot CP attains a minimum.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ill/1986/p5 · Tag JXJABTFH3A · Edit this page on GitHub · Keys: j next, k previous