olymmath

IGO 2020 I3

  • Intermediate

In acute-angled triangle ABCABC ( AC>ABAC > AB ), point HH is the orthocenter and point MM is the midpoint of the segment BCBC . The median AMAM intersects the circumcircle of triangle ABCABC at XX . The line CHCH intersects the perpendicular bisector of BCBC at EE and the circumcircle of the triangle ABCABC again at FF . Point JJ lies on circle ω\omega , passing through X,E,X, E, and FF , such that BCHJBCHJ is a trapezoid ( CB∥HJCB \parallel HJ ). Prove that JBJB and EMEM meet on ω\omega .

Proposed by Alireza Dadgarnia

Dataset text AI-MO AoPS. Quoted with source.

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