olymmath

IGO 2020 A1

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Let M,N,PM,N,P be midpoints of BC,ACBC,AC and ABAB of triangle △ABC\triangle ABC respectively. EE and FF are two points on the segment BC‾\overline{BC} so that ∠NEC=12∠AMB\angle NEC = \frac{1}{2} \angle AMB and ∠PFB=12∠AMC\angle PFB = \frac{1}{2} \angle AMC . Prove that AE=AFAE=AF . Proposed by Alireza Dadgarnia

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