olymmath

IGO 2014

Iranian Geometry Olympiad 2014.

Junior

J2

  • Junior

The inscribed circle of △ABC\triangle ABC touches BC,ACBC, AC and ABAB at D,ED,E and FF respectively. Denote the perpendicular foots from F,EF, E to BCBC by K,LK, L respectively. Let the second intersection of these perpendiculars with the incircle be M,NM, N respectively. Show that S△BMDS△CND=DKDL\frac{{{S}_{\triangle BMD}}}{{{S}_{\triangle CND}}}=\frac{DK}{DL}

by Mahdi Etesami Fard

Answer, solutions and source

J3

  • Junior

Each of Mahdi and Morteza has drawn an inscribed 9393 - gon. Denote the first one by A1A2…A93A_1A_2…A_{93} and the second by B1B2…B93B_1B_2…B_{93}. It is known that AiAi+1//BiBi+1A_iA_{i+1} // B_iB_{i+1} for 1≤i≤931 \le i \le 93 (A93=A1,B93=B1A_{93} = A_1, B_{93} = B_1). Show that AiAi+1BiBi+1\frac{A_iA_{i+1} }{ B_iB_{i+1}} is a constant number independent of ii.

by Morteza Saghafian

Answer, solutions and source

J4

  • Junior

In a triangle ABC we have ∠C=∠A+90o\angle C = \angle A + 90^o. The point DD on the continuation of BCBC is given such that AC=ADAC = AD. A point EE in the side of BCBC in which AA doesn't lie is chosen such that ∠EBC=∠A,∠EDC=12∠A\angle EBC = \angle A, \angle EDC = \frac{1}{2} \angle A. Prove that ∠CED=∠ABC\angle CED = \angle ABC.

by Morteza Saghafian

Answer, solutions and source

J5

  • Junior

Two points X,YX, Y lie on the arc BCBC of the circumcircle of △ABC\triangle ABC (this arc does not contain AA) such that ∠BAX=∠CAY\angle BAX = \angle CAY. Let MM denotes the midpoint of the chord AXAX. Show that BM+CM>AYBM +CM > AY.

by Mahan Tajrobekar

Answer, solutions and source

Senior