olymmath

IrMO 2009 Problem 7

  • Paper 2

For any positive integer nn define E(n)=n(n+1)(2n+1)(3n+1)⋯(10n+1).E(n)=n(n+1)(2n+1)(3n+1)\cdots (10n+1). Find the greatest common divisor of E(1),E(2),E(3),…,E(2009).E(1),E(2),E(3),\dots ,E(2009).

Dataset text AI-MO AoPS. Quoted with source.

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