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OSN 2021 Problem 7

    Given △ABC\triangle ABC with circumcircle ℓ\ell . Point MM in △ABC\triangle ABC such that AMAM is the angle bisector of ∠BAC\angle BAC . Circle with center MM and radius MBMB intersects ℓ\ell and BCBC at DD and EE respectively, (B≠D,B≠E)(B \not= D, B \not= E) . Let PP be the midpoint of arc BCBC in ℓ\ell that didn't have AA . Prove that APAP angle bisector of ∠DPE\angle DPE if and only if ∠B=90∘\angle B = 90^{\circ} .

    Dataset text AI-MO AoPS. Quoted with source.

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