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OSN 2002 Problem 4

    Given a triangle ABCABC where AC>BCAC > BC , DD is located on the circumcircle of ABCABC such that DD is the midpoint of the arc ABAB that contains CC . EE is a point on ACAC such that DEDE is perpendicular to ACAC . Prove that AE=EC+CBAE = EC + CB .

    Dataset text AI-MO AoPS. Quoted with source.

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