olymmath

KöMaL 2025 B5452

    For positive integer n≥3n\geq 3 let points P1P_1, P2P_2, …\ldots, PnP_n be chosen on a parabola with focus FF such that ∠P1FP2=∠P2FP3=…=∠PnFP1=360∘n\angle P_1FP_2=\angle P_2FP_3=\ldots=\angle P_nFP_1=\frac{360^\circ}{n}. Prove that the harmonic mean of the distances FP1FP_1, …\ldots, FPnFP_n eaquals the parameter of the parabola.

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