olymmath

KöMaL 2025 B5444

    In cyclic hexagon ABCDEFABCDEF let PP denote the intersection of diagonals ADAD and CFCF, and let QQ denote the intersection of diagonals AEAE and BFBF. Prove that if BC=CPBC=CP and DP=DEDP=DE, then PQPQ bisects angle BQEBQE.

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2025/b5444 · Tag KF8M5XP3P2 · Edit this page on GitHub · Keys: j next, k previous