olymmath

KöMaL 2023 B5290

    Solve the following equation over the set of positive integers: 3n+4n+⋯+(n+2)n=(n+3)n.3^n+4^n+\dots+{(n+2)}^n= {(n+3)}^n.

    Official text KöMaL. Quoted with source.

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