olymmath

KöMaL 2022 C1726

    Prove that if xx, yy, zz are real numbers such that xy+z+yz+x+zx+y=1,thenx2y+z+y2z+x+z2x+y=0.\frac{x}{y+z}+\frac{y}{z+x}+\frac{z}{x+y}=1, \text{then} \frac{x^2}{y+z}+\frac{y^2}{z+x}+\frac{z^2}{x+y}=0. Find all real numbers satisfying this condition.

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