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KöMaL 2022 B5219

    Prove that ∣a+b+c∣1+∣a+b+c∣≤∣a∣1+∣a∣+∣b∣1+∣b∣+∣c∣1+∣c∣.\frac{|a+b+c|}{1+|a+b+c|}\le \frac{|a|}{1+|a|}+\frac{|b|}{1+|b|}+\frac{|c|}{1+|c|}. for all real numbers aa, bb, cc. On what condition will equality occur?

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