olymmath

KöMaL 2019 B5047

    In a right-angled triangle ABCABC, point DD lies in the interior of leg ACAC, and point EE lies on the extension of hypotenuse ABAB beyond BB. The second intersection of circles ADEADE and BCEBCE (different from EE) is FF. Show that ∠CFD=90∘\angle CFD=90^\circ.

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