olymmath

KöMaL 2016 B4833

    For a sector of a circle of radius RR, smaller than a semicircle, the radius of the inscribed circle is rr, and the length of the chord connecting the endpoints of the boundary arc of the sector is 2a2a. Prove that 1r=1R+1a.\frac 1r= \frac 1R+ \frac 1a.

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