olymmath

KöMaL 2014 B4620

    Prove that for any numbers 0≤a1≤…≤a3n0\le a_1\le\ldots\le a_{3n}, (∑i=13nai)3≥27n2(∑i=1naian+ia2n+i)\bigg(\sum_{i=1}^{3n}a_i\bigg)^3 \ge 27n^2\bigg(\sum_{i=1}^{n}a_ia_{n+i}a_{2n+i}\bigg).

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2014/b4620 · Tag Z8NE2CS3YX · Edit this page on GitHub · Keys: j next, k previous