olymmath

KöMaL 2014 B4607

    The sides of a triangle are aa, bb, cc. A line passes through the centre of the inscribed circle, and intersects side cc at PP, and side bb at QQ. Let APAP=ppand AQAQ=qq. Prove that 1p+1q=a+b+cbc\frac{1}{p} + \frac{1}{q} = \frac{a+b+c}{bc} .

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2014/b4607 · Tag 5QDJR0QPT8 · Edit this page on GitHub · Keys: j next, k previous