KöMaL 2014 B4603

The surface area of a right circular cone is $A$ , its volume is $V$ . Prove that $A^3 \ge$ 72 $\pi^. V^2$ .

Official text KöMaL. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.