KöMaL 2013 C1161

The real numbers $a$, $b$, $c$ in the equation $\frac{x-b-c}{a} +\frac{x-a-c}{b} +\frac{x-a-b}{c}=10$ satisfy $a$+$b$+$c$=0, abc =-48, and $bc$+$ac$+$ab$=-28. Solve the equation.