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KöMaL 2012 B4499

    Let PP be an interior point of an acute-angled triangle A1A2A3A_1 A_2 A_3. The points TiT_i are such that the line segment AiTiA_i T_i touches the circle of diameter PAi+1PA_{i+1} at TiT_i (ii=1,2,3, A4A_4=A1A_1). Show that 2⋅∑i=13AiTi2=∑i=13AiAi+122\cdot \sum_{i=1}^3A_i T_i^2 =\sum_{i=1}^3A_iA_{i+1}^2.

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