olymmath

KöMaL 2011 B4404

    The angles of a polygon A1A2A_1 A_2...A2nA_{2n} are all equal, and its sides satisfy A1A2A_1 A_2=A3A4A_3 A_4=...=A2n−1A2nA_{2n-1} A_{2n} and A2A3A_2 A_3=A4A5A_4 A_5=...=A2nA1A_{2n} A_1. Prove that the polygon is cyclic.

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2011/b4404 · Tag Y02HJ3BGW7 · Edit this page on GitHub · Keys: j next, k previous