olymmath

KöMaL 2008 B4129

    Sequence (ana_n) is defined by the recursion a0a_0=0, a1a_1=1 and ana_n=2an−1a_{n-1}+an−2a_{n-2} for nn>1. Prove that if 2k∣n2^k\mid n , then 2k∣an2^k\mid a_n.

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2008/b4129 · Tag D8ZQ0WZ8Y8 · Edit this page on GitHub · Keys: j next, k previous