olymmath

KöMaL 2008 B4117

    Three lines passing through a point PP are cut by two other lines at the points AA, BB, CCand AA', BB', CC', respectively. Prove that AA′A′PBC→+BB′B′PCA→+CC′C′PAB→=0\frac{AA'}{A'P}\overrightarrow{BC} +\frac{BB'}{B'P}\overrightarrow{CA} +\frac{CC'}{C'P}\overrightarrow{AB}=\mathbf{0}, where the ratios are considered directed.

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