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KöMaL 2006 B3958

    The triangle ABC is right angled at CC and its incentre is OO. The perpendiculars drawn at the point OO to the line segments OAOA and OBOB meet the side ABAB at PP and QQ, respectively. The foot of the perpendicular from PP to the side BCBC is PP', and that from QQ to the side ACAC is QQ'. Prove that the points PP', QQ' and OO are collinear.

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