olymmath

KöMaL 2006 A414

    Prove (xy+yz+zx)(1(x+y)2+1(y+z)2+1(z+x)2)≥94(xy+yz+zx) \left(\frac 1{{(x+y)}^2}+\frac1{{(y+z)}^2}+\frac1{{(z+x)}^2}\right) \ge\frac94 for all positive reals xx, yy, zz.

    Official text KöMaL. Quoted with source.

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