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KöMaL 2005 C828

    Find the area of the triangle bounded by the lines x+y=2005,x2005+y2006=1,x2006+y2005=1x+y=2005, \frac{x}{2005}+ \frac{y}{2006}=1, \frac{x}{2006}+ \frac{y}{2005}=1

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