olymmath

HMMT November 2024 U27

  • Guts
  • Answer

For any positive integer nn, let f(n)f(n) be the number of ordered triples (a,b,c)(a, b, c) of positive integers such that

  • max (a,b,c)(a, b, c) divides nn and
  • gcd⁡(a,b,c)=1\operatorname{gcd}(a, b, c)=1.

Compute f(1)+f(2)+⋯+f(100)f(1)+f(2)+\cdots+f(100).

Dataset text NuminaMath olympiads. Quoted with source.

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1000000

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