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HMMT November 2021 U23

  • Guts

Side AB‾\overline{A B} of △ABC\triangle A B C is the diameter of a semicircle, as shown below. If AB=3+3,BC=32A B=3+\sqrt{3}, B C=3 \sqrt{2}, and AC=23A C=2 \sqrt{3}, then the area of the shaded region can be written as a+(b+cd)πe\frac{a+(b+c \sqrt{d}) \pi}{e}, where a,b,c,d,ea, b, c, d, e are integers, ee is positive, dd is square-free, and gcd⁡(a,b,c,e)=1\operatorname{gcd}(a, b, c, e)=1. Find 10000a+1000b+100c+10d+e10000 a+1000 b+100 c+10 d+e.

Dataset text NuminaMath olympiads. Quoted with source.

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