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HMMT November 2020 E7

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In triangle ABCA B C with AB=8A B=8 and AC=10A C=10, the incenter II is reflected across side ABA B to point XX and across side ACA C to point YY. Given that segment XYX Y bisects AIA I, compute BC2B C^{2}. (The incenter II is the center of the inscribed circle of triangle ABCA B C.)

Dataset text NuminaMath olympiads. Quoted with source.

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